Question

Na2S2O3 + AgBr NaBr + Na3ſAg(S203)2] What is

the mass of NaBr that will be produced from 42.7 g of AgBr?

Answer 1

Mass of NaBr produced = 23.67 g

Step-by-step explanation:

Given data:

Mass of AgBr = 42.7 g

Mass of NaBr produced = ?

Solution:

Chemical equation:

2Na₂S₂O₃ + AgBr → NaBr + Na₃(Ag(S₂O₃)₂

Number of moles of AgBr:

Number of moles = mass/molar mass

Number of moles = 42.7 g/ 187.7 g/mol

Number of moles = 0.23 mol

now we will compare the moles of AgBr with NaBr.

AgBr : NaBr

1 : 1

0.23 : 0.23

Mass of NaBr:

Mass = number of moles × molar mass

Mass = 0.23 mol × 102.89 g/mol

Mass = 23.67 g