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A jeweler heated a sample of silver from 22.0°C to 46.0°C. The specific heat of silver is

0.235 J/gºC. If the silver absorbed 26.0 J of heat, what is the mass of the silver?
please help me!

1 Answer

4 votes

The mass of the silver : 4.6 g

Further explanation

Heat can be calculated using the formula:

Q = mc∆T

Q = heat, J

m = mass, g

c = specific heat, joules / g ° C

∆T = temperature difference, ° C / K

∆T = temperature difference :


\tt 46-22=24^oC

The specific heat of silver is 0.235 J/gºC

Q = heat = 26 J

The mass :


\tt mass(m)=(Q)/(c.\Delta T)\\\\m=(26)/(0.235* 24)\\\\m=4.6~g

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