Question

The X coordinate of a point P on X axis is 4 and the y coordinate of a point Q on y axis is 3. Find the distance of PQ.​

Answer 1

5 units

Explanation:

Since The X coordinate of a point P on X axis is 4 and the y coordinate of a point Q on y axis is 3 the points are

P (4 , 0) and Q(0 , 3)

The formula to calculate distance between two points

`PQ=√((x_2-x_1)^2+(y_2-y_1)^2) \\PQ=√((0-4)^2+(3-0))\\PQ=√((4)^2+(3)^2)\\PQ=√(16+9) \\PQ=√(25) \\PQ=5\ units\ \\`

IMPORTANT!

As we take the square root of 25 we get two values +5 and -5 we always take the positive value because distance can never be negative.