Question

(i) A vessel of 110 mL capacity contains a certain amount of gas at 33 "C and 2.4 bar pressure. The gas is transferred to another vessel of volume 160 mL at 33 °C. What would be its pressure?

(ii)On a ship sailing in Ocean where temperature is 26.2degree Celsius a balloon filled with 4L air. What will be the volume of the balloon when the ship reaches Indian Ocean, where temperature is 38.1 degree Celsius?​

Answer 1

a) 1.65 bar

b) 4.2 L

Step-by-step explanation:

From Boyle's law(since temperature is constant);

P1V1= P2V2

P2 = P1V1/V2

V1 = 110 ml

T1= 33 + 273 =306 K

P1 = 2.4 bar

V2 = 160 ml

T2 = 33 + 273 = 306

P2 =?

P2 = 2.4 * 110/160

P2 = 1.65 bar

2)

T1 = 26.2 + 273 = 299.2 K

V1 = 4L

T2 = 38.1 + 273 = 311.1

V2 =?

From Charles's law;

V1/T1 = V2/T2

V1T2 = V2T1

V2 = V1T2/T1

V2 = 4 * 311.1/299.2

V2 = 4.2 L