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PLEASE HELP URGENT!!

c) 2Al(s) + 3C12 (g) → 2AICI3
Reactant Side-
Product Side-
Oxidizing Agents
Reducing Agent

User Cramer
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1 Answer

4 votes

Answer:

Reactant Side = Al + Cl₂

Product Side = AlCl₃

Oxidizing Agents = chlorine

Reducing Agent = aluminum

Step-by-step explanation:

Chemical equation:

2Al + 3Cl₂ → 2AlCl₃

In this chemical equation Al and Cl₂ are reactants while AlCl₃ is product.

2Al° + 3Cl₂° → 2Al⁺³Cl⁻¹₃

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

In given reaction Al is oxidized because oxidation increase from zero to +3. It is thus reducing agent.

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

In given reaction chlorine is reduced because its oxidation state is decreased from zero to -1. Chlorine is oxidizing agent.

Oxidizing agents:

Oxidizing agents oxidize the other elements and itself gets reduced.

Reducing agents:

Reducing agents reduced the other element are it self gets oxidized.

User LouieC
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