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1 vote
How many moles of oxygen would
be consumed to produce 68.1 g
water?

How many moles of oxygen would be consumed to produce 68.1 g water?-example-1
User Asfallows
by
6.5k points

2 Answers

4 votes

Answer: 4.75 moles of oxygen

Step-by-step explanation:

User Aartist
by
5.6k points
6 votes

Answer:

4.75 moles of oxygen would be consumed by water

Step-by-step explanation:

Given data:

Mass of water produced = 68.1 g

Number of moles of oxygen consumed = ?

Solution:

Chemical equation:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

Number of moles of water:

Number of moles = mass/molar mass

Number of moles = 68.1 g/ 18 g/mol

Number of moles = 3.8 mol

Now we will compare the moles of water with oxygen.

H₂O : O₂

4 : 5

3.8 : 5/4×3.8 = 4.75 mol

User Jeff Bramwell
by
5.9k points