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If ABCD is a square and AC= 26, what is the length of BC

If ABCD is a square and AC= 26, what is the length of BC-example-1
User Stmi
by
5.0k points

2 Answers

3 votes

Answer: aprox 18.38

Explanation:

you have a AC=, which is the hypothenuse of the right triangle, and isosceles

ABC

AB=BC, sides of a square

remember c^2=a^2+b^2 but and b are equal so we can say

c^2= 2a^2

c=a
√(2), 26/
√(2)=a

a=(26
√(2))2=18.38

User Rohan Khude
by
6.2k points
3 votes

Answer:

BC = 18.385

Explanation:

You can look at ABC as a right triangle and use the Pythagorean theorem to solve for BC. 26 squared is 676, 676 divided by 2 is 338, and finally the square root of 338 is 18.385. This is the length of BC and AB as well. Hope that helped

User David Z
by
5.2k points