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How many moles of N2O5 are needed
to produce 7.90 g of NO2?

How many moles of N2O5 are needed to produce 7.90 g of NO2?-example-1
User Nikerboker
by
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1 Answer

6 votes

Answer:

0.085 moles of N₂O₅ are needed

Step-by-step explanation:

Given data:

Mass of NO₂ produces = 7.90 g

Moles of N₂O₅ needed = ?

Solution:

2N₂O₅ → 4NO₂ + O₂

Number of moles of NO₂ produced :

Number of moles = mass/ molar mass

Number of moles = 7.90 g/ 46 g/mol

Number of moles = 0.17 mol

now we will compare the moles of NO₂ with N₂O₅.

NO₂ : N₂O₅

4 : 2

0.17 : 2/4×0.17 = 0.085 mol

Thus, 0.085 moles of N₂O₅ are needed.

User RadekEm
by
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