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What is the remainder when (4x^3 + 3x^2 - 17x - 12) is divided by (x - 1)?
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What is the remainder when (4x^3 + 3x^2 - 17x - 12) is divided by (x - 1)?

User Not A JD
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1 Answer

4 votes

Answer:

remainder is 4x^2+7x-10- 22/x-1

Explanation:

User John Skoubourdis
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