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Anybody know this question

Anybody know this question-example-1
User Smarques
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1 Answer

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Answers :-

  • sinB = 12/13
  • cosB = 5/13
  • tanB = 12/5

Here as by the given information ,

♦ sinA = Opposite/Hypotenuse

♦ cosA = Adjacent/Hypotenuse

♦ TanA = Opposite/adjacent

So here we need to find the same for angle B so we need to use the same formulas for angle B also .

sinB = Opposite/Hypotenuse = 12/13

cosB = Adjacent/Hypotenuse = 5/13

tanB = Opposite/Adjacent = 12/5

User Cengiz
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