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Write an equation of the line in slope-intercept form.

f(3)=-2, f(0)=1

User LarsH
by
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1 Answer

4 votes

Answer:

The equation of the line in slope-intercept form is y = -x + 1

Explanation:

The slope-intercept form of the linear equation is y = m x + b, where

  • m is the slope of the line
  • b is the y-intercept ⇒ value y at x = 0

The rule of the slope is m =
(y2-y1)/(x2-x1) , where

  • (x1, y1) and (x2, y2) are two points on the line

∵ f(x) = y ⇒ is the function of the set of ordered pairs (x, y)

f(3) = -2 is the point (3, -2)

f(0) = 1 is the point (0, 1)

∴ x1 = 3 and y1 = -2

∴ x2 = 0 and y2 = 1

→ Substitute them in the rule of the slope to find it

∵ m =
(1--2)/(0-3) =
(1+2)/(-3) =
(3)/(-3)

m = -1

→ Substitute it in the form of the equation above

∵ y = -1(x) + b

∴ y = -x + b

∵ b is the value of y at x = 0

∵ at x = 0, y = 1

b = 1

∴ y = -x + 1

The equation of the line in slope-intercept form is y = -x + 1

User Diogo Moreira
by
5.7k points
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