Question

1) In a bag of red and green sweets, the ratio of red sweets to green sweets is 3:7. If the bag contains 49 green sweets, how many red sweets are there?

Answer 1

Red sweets = 21

Explanation:

Let there are 3x red sweets and 7x green sweets.

Total no of 49 green sweets.

ATQ,

7x = 49

x = 7

Red sweets = 3x

= 3(7)

= 21

Hence, there are 21 red sweets.