Question

PLEASE HELP!

Find the real or imaginary solutions of the following equation by factoring.

y^3 + 27 = 0

Answer 1

Do u still need the answer?

Explanation:

Answer 2

1. -3
2. 1.5(1 + i√3)
3. 1.5(1 - i√3)

Explanation:

• y³ + 27 = 0
• (y + 3)(y² - 3y + 9) = 0

1. y + 3 = 0 ⇒

• y = -3

2. y² - 3y + 9 = 0

• y = (3 ±√(3² -4*9))/2
• y = (3 ± √-27)/2
• y = (3 ± i√27)/2
• y = 3/2(1 ± i√3)
• y = 1.5(1 ± i√3)