Answer:
67.0 g Lead (ll) Nitrate
Step-by-step explanation:
first, find you mass for each element
Pb= 207 g
N=14 g
207(2)+14=428 g
now convert to grams using the standard moles conversion
0.270 moles (248 g/1 mole) = 66.96
round to the correct number of significant figures, 3.
66.96= 67.0 g