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9 votes
9 votes
I need help with this like right now

I need help with this like right now-example-1
User Amuniz
by
2.3k points

2 Answers

22 votes
22 votes

Answer:

125º

Explanation:

An exterior angle of a triangle is equal to the sum of its opposite interior angles.

In this case, 146º is the exterior angle and 21º and xº are the interior angles.

We can set up an equations 146=21+x

By subracting 21, we find that x=125

User KarelZe
by
2.2k points
11 votes
11 votes

Answer:


\boxed{\boxed{\tt x=125^(\circ)}}

Explanation:

To solve this problem we need to apply the triangle exterior angle property.

*Exterior angle of a triangle is equal to the sum of its two opposite interior angles.*

146 ° here, is an exterior angle of the triangle, and 21 °/x are opposite interior angles.


\tt 146^(\circ)=21^(\circ)+x

Switch sides:


\longmapsto\tt 21^(\circ)+x=146^(\circ)

Subtract 21 from both sides:


\longmapsto\tt 21^(\circ)+x-21^(\circ)=146^(\circ)-21^(\circ)


\longmapsto\tt x=125^(\circ)

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User Subsub
by
3.1k points
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