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10 po 6) If a 47 kilogram object accelerates suddenly at 15 m/s^2, how much FORCE was applied to the object? 705 N 27 N 12 N
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10 po 6) If a 47 kilogram object accelerates suddenly at 15 m/s^2, how much FORCE was applied to the object? 705 N 27 N 12 N
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May 17, 2021
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10 po
6) If a 47 kilogram object accelerates suddenly at 15 m/s^2, how much
FORCE was applied to the object?
705 N
27 N
12 N
Physics
high-school
Petomalina
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By the Newtons Second Law:
F = ma
F = (47 kg)(15 m/s²)
F = 705 N
Muhammad Azeez
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May 24, 2021
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Muhammad Azeez
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