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10 po 6) If a 47 kilogram object accelerates suddenly at 15 m/s^2, how much FORCE was applied to the object? 705 N 27 N 12 N
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1 vote
10 po

6) If a 47 kilogram object accelerates suddenly at 15 m/s^2, how much
FORCE was applied to the object?
705 N
27 N
12 N

User Petomalina
by
6.1k points

1 Answer

6 votes

By the Newtons Second Law:

F = ma

F = (47 kg)(15 m/s²)

F = 705 N

User Muhammad Azeez
by
6.4k points
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