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What is the solution of the linear-quadratic system of equations?
y=x^2+5x−3
y−x=2

2 Answers

3 votes

Answer:

x = 1, y = 3

x = -5, y = -3

Explanation:

Point Form:

(1,3) , (-5, -3)

User Pranav Kumar H M
by
4.0k points
7 votes

y = x²+5x−3

y−x = 2 = y = x+2

----------------------------------

x+2 = x²+5x-3

x² + 4x -5 =0

(x+5)(x-1)=0

x ₁= -5

x₂ = 1

-----------------------------------

y₁ = -5+2

y₁ = -3

y₂ = 1+2

y₂ = 3

User Dan Bracuk
by
4.0k points