Question

Force of 92 N is exerted horizontally on an 18 kg box of books. The coefficient of kinetic friction between the floor and the box is 0.35. Find the net work done on the box.

Answer 1

Complete Question

Force of 92 N is exerted horizontally on an 18 kg box of books, initially at rest , 7.6 m across a floor . The coefficient of kinetic friction between the floor and the box is 0.35. Find the net work done on the box.

Answer:

The value is
`W_(net) = 230 \ J`

Step-by-step explanation:

From the question we are told that

The force exerted is
`F = 92 \ N`

The mass of the box is
`m = 18 \ kg`

The coefficient of kinetic friction is
`\mu_k = 0.35`

The distance covered is
`d = 7.6 \ m`

Generally net workdone is mathematically represented as

`W_(net) = F_(net) * d`

Here
`F_(net)` is the net force experienced by the box of books which is mathematically represented as

`F_(net) = F - \mu_k * m * g`

=>
`F_(net) = 30.26 \ N`

So

`W_(net) = 30.26 * 7.6`

=>
`W_(net) = 230 \ J`