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What is the base of the exponent in the function fx=3(3/8)^2

User Mcbowes
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Answer:

by definition, an exponential function with base c is defined by h (x) = ac^x

where a ≠0, c > 0 , b ≠1, and x is any real number.

The base, c, is a constant and the exponent, x, is a variable.

so if we have f(x)=3(3\8)^2x, this equivalent to f(x)=3(3\8)^y(x),

where y (x)=2x,

therefore, the base is 3/8, and the variable is the function y (x)=2x, it is 4

Explanation:

User Rover
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