Answer:
first
Explanation:
f(n) =56 (0.5)^(n-1)
f(1) = 56 (0.5)^0= 56*1 = 56
f(2) =56 (0.5)^1 = 56* 0.5 = 28
f(3) = 56 (0.5)^2 = 14
f(4) = 56 (0.5)^3 = 7
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