Question

An arcade ball is thrown with an initial speed of 7.0 m/s and follows the trajectory shown. The ball enter the basket .95 seconds after it is launched. What are the distances x and y?

Answer 1

Complete Question

The diagram for this question is shown on the first uploaded image

Answer:

`x = 4.70 \ m` ,
`y = 0.2803 \ m`

Step-by-step explanation:

From the question we are told that

The initial velocity of the arcade ball is
`u = 7.0 \ m/s`

The time taken by the ball to enter the basket is
`t = 0.95 \ s`

Generally the x -component of the initial velocity is

`u_x = 7 * cos (45)`

=>
`u_x = 4.95 \ m/s`

Generally the y -component of the initial velocity is

`u_x = 7 * sin(45)`

=>
`u_y = 4.95 \ m/s`

Generally the distance x is mathematically represented as

`x = u_x * t`

=>
`x = 4.95 * 0.95`

=>
`x = 4.70 \ m`

Generally from kinematic equation the distance y is mathematically represented as

`y = u_y * t - (1)/(2) * g * t^2`

=>
`y = 4.95 * 0.95 - (1)/(2) * 9.8 * 0.95^2`

=>
`y = 0.2803 \ m`