Question

and object with a mass of 2.3kg had a force of 6.2 newton’s applied to it. what is the resulting acceleration of the object?

Answer 1

`\boxed {\boxed {\sf 2.7 \ m/s^2}}`

Step-by-step explanation:

Force is the product of mass and acceleration.

`F=ma`

The mass of the object is 2.3 kilograms. The force is 6.2 Newtons or 6.2 kilogram meters per second squared.

• m= 2.3 kg
• F= 6.2 kg*m/s²

Substitute the values into the formula.

`6.2 \ kg*m/s^2 = 2.3 \ kg *a`

We are solving for the acceleration, so we must isolate the variable a.

It is being multiplied by 2.3 kilograms. The inverse operation of multiplication is division. Divide both sides by 2.3 kg.

`\frac {6.2 \ kg*m/s^2}{2.3 \ kg} = (2.3 \ kg *a)/(2.3 \ kg)`

`\frac {6.2 \ kg*m/s^2}{2.3 \ kg} =a`

`2.69565217 \ m/s^2=a`

The original measurements of force and mass have 2 significant figures, so our answer must have the same. For the number we found, that is the tenths place. The 9 in the hundredht place tells us to round the 6 up to a 7.

`2.7 \ m/s^2 \approx a`

The acceleration is approximately 2.7 meters per second squared.