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This circle is centered at the origin, and the length of its radius iS 6. What is

the circle's equation?

1 Answer

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\sf{\qquad\qquad\huge\underline{{\sf Answer}}}

The equation of circle in standard form can be represented as :


\qquad \sf  \dashrightarrow \:(x - h) {}^(2) + (y - k) {}^(2) = r {}^(2)

where,

  • h = x - coordinate of centre = 0

  • k = y - coordinate of centre = 0

  • r = radius of circle = 6 units

now, let's plug in the values :


\qquad \sf  \dashrightarrow \:(x - 0) {}^(2) + (y - 0) {}^(2) = 6 {}^(2)


\qquad \sf  \dashrightarrow \: {x}^(2) + {y}^(2) = 36

That's the required equation of circle.

User Michael Lafayette
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