532,271 views
40 votes
40 votes
Quadrilateral ABCD has these angle measures:

mzA= 124°
mzB = (8x - 2y)
mzC=(16x-7y)°
m2D = 56°
What values of x and y make ABCD a parallelogram?
x=6 and y=-4
x = -6 and y=-4
x = 6 and y = 4
x = -6 and y = 4

Quadrilateral ABCD has these angle measures: mzA= 124° mzB = (8x - 2y) mzC=(16x-7y-example-1
User Gsinha
by
2.7k points

1 Answer

16 votes
16 votes

Answer:

x=6 and y = -4

Explanation:

Opposite angles of a parallelogram are congruent so:

  • Angle A is congruent to Angle C
  • 124 = 16x - 7y
  • 16x = 124 + 7y

  • Angle B is congruent to angle D
  • 8x - 2y = 56
  • 8x = 56 + 2y
  • 16x = 112 + 4y

This means that:

  • 112 + 4y = 124 + 7y
  • 4y = 12 + 3y
  • -3y = 12
  • y = -4

So, 16x = 124+7(-4) = 96, meaning x=6

User RamelHenderson
by
3.3k points