Question

How many molecules of HCI (hydrochloric acid) are formed when 50.0 g of

water reacts according to the following balanced reaction? Assume excess
iodine trichloride, ICl3.
2 ICl3 + 3 H₂O → ICI+HIO3 + 5 HCI

Answer 1

To find the number of molecules of HCl formed when 50.0 g of water reacts, calculate the number of moles of HCl. Using the balanced equation, 2 moles of HCl are produced for every 1 mole of the reactants. So, multiplying the number of moles by 2 gives the number of HCl molecules formed.

Step-by-step explanation:

According to the balanced equation, 2 moles of HCI are produced for every 1 mole of the two reactants. Therefore, to find the number of HCl molecules formed, we need to calculate the number of moles of HCl.

We know that 50.0 g of water is used in the reaction. To calculate the number of moles, we can use the molar mass of water which is 18.015 g/mol.

Using the formula:

moles = mass / molar mass

moles = 50.0 g / 18.015 g/mol = 2.775 mol

Since the balanced equation shows that 2 moles of HCI are formed, we can multiply the number of moles by 2 to obtain the number of HCI molecules formed:

Number of HCI molecules = 2.775 mol x 2 = 5.55 mol

Answer 2

mol H₂O: 50 : 18 g/mol = 2.7

mol HCl = 5/3 x 2.7 (based on coefficient reaction) = 4.5

molecules HCl = 4.5 x 6.02 x 10²³ = 2.71 x 10²⁴