Question

A sample of a gas has volume 78.5ml at 318.15 K.. What Volume at will the sample occupy at

273. 15 K when the pressure is held constant?
Use charles Law formula of volume. ​

Answer 1

Charles'law:

V₁/T₁=V₂/T₂

78.5/318.15 = V₂/273.15

V₂=67.4 ml

Answer 2

Required answer :

We know that,

Charle's Law :

• 
  `\red{\boxed{ \sf (V_(1))/(T_(1)) \: = \: (V_(2))/(T_(2)) }} \: \pink \bigstar`

We have :

• V_1 = 78.5 ml
• T_1 = 318.15 K
• T_2 = 273.15 K
• V_2 = ?

(V is volume and T is temperature)

Substituting the values :

`\implies \: \sf (78.5)/(318.15) \: = \: ( V_2)/(273.15) \\ \\ \implies \: \sf 78.5 *273.15 \: = \: V_2 * 318.15 \\ \\ \implies \: \sf { 21442.275 \: = \: V_2 * 318.15} \\ \\\implies \: \sf {V_2 = ( 21442.275 )/(318.15)} \\ \\ \implies \: \bf {V_2 = 67.3 \: (approx) }`