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Step-by-step explanation:
1. The Law of Sines says each side length is proportional to the sine of the opposite angle. As with any proportion, it can be written four ways. Corresponding parts can be numerators, denominators, or parts of the same ratio.
Where a, b, c are the side lengths, and A, B, C are the respective opposite angles, some of the formulations are ...
![(\sin(A))/(a)=(\sin(B))/(b)=(\sin(C))/(c)\\\\(a)/(\sin(A))=(b)/(\sin(B))=(c)/(\sin(C))\\\\(a)/(b)=(\sin(A))/(\sin(B))\quad (a)/(c)=(\sin(A))/(\sin(C))](https://img.qammunity.org/2021/formulas/mathematics/college/kf8bc45gk753lj7di54m2nfx9vz80v0kyj.png)
When solving triangles, you need ...
- at least one angle and its opposite side, and
- any other angle or side.
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2. The Law of Cosines is conventionally written as ...
![c^2=a^2+b^2-2ab\cos(C)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/wyi831u7zx4emcet6wpi7elj66wnxtlqo1.png)
where c is the side opposite angle C, and a and b are the sides bounding angle C. Any of the side and angle designations can be interchanged, so, for example, it can also be written ...
![a^2=b^2+c^2-2bc\cos(A)](https://img.qammunity.org/2021/formulas/mathematics/college/q4523cd9552xjeuj5m682l1y4ot39lr323.png)
The equation can be solved for the angle, which gives ...
![A=\arccos{\left((b^2+c^2-a^2)/(2bc)\right)}](https://img.qammunity.org/2021/formulas/mathematics/college/trnt9ssfolrtua2odin2bl9ja6jh3ocprk.png)
When using this formula, you need ...
- two sides and one angle, or
- three sides
If the two given sides do not bound the given angle, the Law of Sines may be easier to use. Using the Law of Cosines will result in a quadratic equation for the unknown side, whereas the Law of Sines will give a linear equation.
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3. When the enclosed angle is a right angle, the Law of Cosines degenerates to a statement of the Pythagorean theorem. (The cosine term vanishes.)