Question

A 2200-kg railway freight car coasts at 4.1 m/s underneath a grain terminal, which dumps grain directly down into the freight car. If the speed of the loaded freight car must not go below 3.4 m/s, what is the maximum mass of grain that it can accept?

Answer 1

The answer is "
`2.41 * 10^3`"

Step-by-step explanation:

Given:

`m_i = 2000 \ kg \\\\v_i= 4.1 \ (m)/(s) \\\\v_f = 3.4 \ (m)/(s) \\`

Using formula:

`\to m_iv_i = m_fv_f \\\\\to m_f= (m_iv_i)/(v_f)`

`p_i, p_f` = system initial and final linear momentum.

`V_i, v_f` = system original and final linear pace.

`m_i` = original weight of the car freight.

`m_f`= car's maximum weight

`= ( 2000 * 4.1)/(3.4)\\\\= ( 8.2* 10^3)/(3.4)\\\\= 2.41 * 10^3`

`\boxed{m_f = 2.41 * 10^3}`