Answer:
90 V
Step-by-step explanation:
What is the magnitude of the average induced emf in the coil?
Given that
The number of turns, N = 15
Area of coil, A = 0.4 m²
Magnetic field of the coil, B = 0.75 T
Time taken, t = 0.05 s
The average induced EMF in a coil due to the presence of a magnetic field is given as:
v = -NBA/t
When we substitute the values directly, we have
v = - (15 * 0.4 * 0.75)/0.05
v = -4.5 / 0.05
v = -90
Therefore, the magnitude of the induced emf is 90 V