126k views
1 vote
a retired statistician was interested in determining the average cost of a 200000 term life insurance policy for a he randomly sampled 65 subjects what value of alpha was used to create this confidence interval

1 Answer

6 votes

Answer:

The correct option is the second option

Explanation:

From the question we are told that

The average cost is
\mu = \$ 200 000.00

The sample size is n = 65

The upper limit of the 95% confidence interval is $1050.00

The lower limit of the 95% confidence interval is $850.00

From the question we are told the confidence level is 95% , hence the level of significance is


\alpha = (100 - 95 ) \%

=>
\alpha = 0.05

a retired statistician was interested in determining the average cost of a 200000 term-example-1
User Zachary Oldham
by
5.2k points