Question

A loaded flatbottom barge floats in fresh wa-ter. The bottom of the barge is 4.09 m belowthe water line. When the barge is empty thebarge’s bottom is only 1.8 m below the waterline.What is the difference between the pressureon the bottom of the loaded barge and thepressure at the water line?Answer in units of Pa.006 (part 2 of 2) 10.0 pointsIf the surface area of the bottom of the barge

Answer 1

The value is
`\Delta P = 40082 \ Pa`

Step-by-step explanation:

From the question we are told that

The length of the bottom of the barge below the water line when loaded is
`d_2 = 4.09 \ m`

The length of the bottom of the barge below the water line when empty is
`d_1 = 1.80 \ m`

Generally the difference in pressure is mathematically represented as

`\Delta P = \rho * g * d_2`

Here
`\rho` is the density of water with value
`\rho = 1000 \ kg/m^3`

`\Delta P = 1000 * 9.8 * ( 4.09 )`

=>
`\Delta P = 40082 \ Pa`