Answer:
10
Step-by-step explanation:
From the information given:
The input for a fixed voltage range for SQNR when N = 7 is 32 dB
Required: To find the minimum value of N such that SQNR ≥ 46 dB
For an ADC:
SQNR = 6.02(N) + 1.76 dB
Comparing both SQNR such that SQNR₁ = 32 dB and SQNR₂ = 46 dB
Taking the ratio:
![(32 - 1.76)/(46-1.76)= (7)/(N_(minimum))](https://img.qammunity.org/2021/formulas/engineering/college/ig2aaahkab876x3xbaxcvpkcxkxl7wjq6l.png)
![(30.24)/(44.24)= (7)/(N_(minimum))](https://img.qammunity.org/2021/formulas/engineering/college/x98jcbpzeph7l0n0ztl3irdda77mae02kt.png)
![N_(minimum) * 30.24 = 44.24 * 7](https://img.qammunity.org/2021/formulas/engineering/college/r1rn4vne1iy3lhphflpbz479wvdxtauflu.png)
![N_(minimum) = (44.24 * 7)/(30.24)](https://img.qammunity.org/2021/formulas/engineering/college/o6hcvoeij49gv75qvbts6hzdpomcyw1c3e.png)
![N_(minimum) = 10.24](https://img.qammunity.org/2021/formulas/engineering/college/enqwli9nm4k416q6aekd4ingcldbw2v5oy.png)
![N_(minimum) \simeq 10](https://img.qammunity.org/2021/formulas/engineering/college/p6mhfnnt5s4pzd8wg63e5qmwr5vn24ki1f.png)