Answer:
2.48*10^-5 N/m
Step-by-step explanation:
The magnitude force per unit length on parallel wires separated by a distance D and currents I1 & I2.
F/l = µ.I1.I2/2πd
Where
µ = 4π *10^-7
I1 = 1.80 A
I2 = 3.45 A
d = 5 cm = 0.05 m
F/l = (4π*10^-7 * 1.8 * 3.45) / (2 * π * 0.05)
F/l = (1.2568*10^-6 * 6.21) / 0.3142
F/I = 7.8*10^-6 / 0.3142
F/l = 2.48*10^-5 N/m
Therefore, the magnitude of the force per unit length is 2.48*10^-5 N/m