Question

Find the value of the spring constant for the spring in Trial I. Use 0.367 s for the value of the period. The mass of the suspended block is 0.400 kg.

Answer 1

117.28 N/m

Step-by-step explanation:

step one:

given

Period T= 0.367s

mass m= 0.4kg

Required

the spring constant k

Step two:

The expression for the period, mass and spring constant relation is

T=2π√m/k

making k subject of the formula

`T/2 \pi = \sqrt m/k`

square both sides

`(T/2 \pi)^2= m/k`

`k= m/(T/2 \pi)^2`

`k=0.4/(0.367/2*3.142)^2`

`k=0.4/(0.05840)^2`

`k=0.4/0.0034105\\\\k=117.28 N/m`