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What is the range of the function y=3√x+8?
0-∞ 0-8 O 0≤y<∞
O 2≤y<∞

1 Answer

2 votes

Answer:
y \geq 8

Explanation:

The range of
y=√(x) is
y \geq 0

Multiplying this by 3, we get the range of
y=3√(x) is still
y \geq 0

Adding 8 to this, we get the range of
y=3√(x)+8 is
y \geq 8.

User Harshal Chaudhari
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