Question

What is the frequency of the fundamental mode of vibration of a steel piano wire stretched to a tension of 440 N? The wire is 0.600 m long and has a mass of 5.60 grams.

a. 234 Hz
b. 517 Hz
c. 312 Hz
d. 366 Hz
e. 295 Hz

Answer 1

Complete Question

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Answer:

Step-by-step explanation:

From the question we are told that

The tension is
`T = 440 \ N`

The length of the wire is
`l = 0.600 \ m`

The mass is
`m = 5.60 \ g = 0.0056 \ kg`

Generally the frequency is mathematically represented as

`f = (1)/(2l) * \sqrt{(T)/((m)/(l) ) }`

=>
`f = (1)/(2 * 0.600 ) * \sqrt{(440)/((0.0056)/(0.600) ) }`

=>
`f = 181 \ Hz`