Explanation:
The problem can be written as
Ar = where A = 5×6 matrix. dim(NullA)=1 as all the multiples of Ar=0
are the multiple of one non zero solution.
Since A is 5×6 , A n= 6
rank(A)= n-dim(Nul A)= n-1= 6-1=5
now, imagine A as 5 dimensional subspace of R^5( As A has 5 rows)
Therefore Col(A)= R^5
This means that Ar = b has a solution for every b.