Answer:
0.0625kg/s
0.9031kW
Step-by-step explanation:
At state 1, enthalpy and entropy are determined from table R-134a.
P1 = 400kpa
h1 = 255.55kj
S1 = 0.92691
h2 = 270kj/kg
Enthalpy at states 3 and 4 can be gotten from the pressure and state with data from a-12
h3 = h4 = 95.48kj/kg
1.)
The mass flow rate
= QL/h1 - h4
= 10/255.55-95.48
= 10/160.07
= 0.0625kg/s
2.)
The power requirement
= 0.0625(270-255.55)
= 0.9031 kW