Question

A disk rotates at an angular acceleration of 20 rad/s 2 about its axis. The radius of the disk is 20cm. What is the centripetal acceleration at a point on the edge of the disk when its angular speed is 16 rad/s

Answer 1

The answer is 1280m/s^2

Step-by-step explanation:

Step one:

given

Angular acceleration of 20 rad/s^2

The radius of the disk is 20cm = 0.2m

angular speed is 16 rad/s

Required

The centripetal acceleration

Step two

The expression for the centripetal acceleration is

`a_c = ( \omega^2)/(r)`

a_c =centripetal acceleration

v =velocity

r =radius

Substituting we have

`a_c = ( 16^2)/(0.2)\\\\a_c = (256)/(0.2)\\\\ a_c = \1280m/s^2`