Question

If you place a weighing boat (0.229 g) on the balance, hit the tare/zero button, weigh 0.678 g of NaCl, then remove everything from the balance, then the balance will read ________.

Answer 1

The weighing balance will read New weight = -0.229

Step-by-step explanation:

From the question we are told that

The mass of the boat is m = 0.229 g

The mass of the NaCl is
`m_1 = 0.678 \ g`

Generally what the tare/zero button does is to set the reading of the weighing balance to zero , so

when this button is pressed the balance reads zero , now when the NaCl is placed on the balance , it reads 0.678 g , now when both the weighing boat and NaCl (i.e everything) is removed , the balance reads

-0.229 g

The reason for this is , when the weighing boat was on the weighing balance , the tare / zero button was pressed , which made the balance to assume the weighing boat as part of it make up hence the zero reading on the balance now when it is then removed the balance now performs a calculation like this

New weight = 0 - mass of the boat

=> New weight = 0 - 0.229

=> New weight = -0.229 g

Answer 2

-0.229 g

Step-by-step explanation:

Given that:

the mass of the weighing boat = 0.229 g

The mass of the balance and the weighing boat w₁ = 0.229 g

After it hit the tare/zero button

The mass of the balance and the weighing boat w₂ = 0.000 g; &

the mass of NaCl w₃ = 0.678 g

If we remove all the components from the balance; the balance will read:

= 0.000 g- 0.229g

= -0.229 g