Question

Write the charge balance for an aqueous solution of arsenic acid, H3AsO4, in which the acid can dissociate to H2AsO24 , HAsO24 2, and AsO34 2. Look up the structure of arsenic acid in Appendix G and write the structure of HAsO24 2.

Answer 1

Kindly check the explanation section.

Step-by-step explanation:

When the Arsenic acid,H3AsO4 is put in water it dissociates to form or give out 1 proton, 2 protons or 3 protons that is 1H^+, 2H^+ and 3H^+. Check the equation showing the dissociation reactions as given below;

H3AsO4 ===========> H^+ + AsO4^-

H3AsO4 ===========> 2H^+ + AsO4^2-

H3AsO4 ===========> 3H^+ + AsO4^3-

Therefore, the total charge balance is given as:

[H^+] =[OH^-] + [ AsO4^-] + 2[ AsO4^2-] + 3[ AsO4^3-].

Kindly note that the [OH^-] is from water.