Answer:
The solution to this question can be defined as follows:
Explanation:
Please find the complete question in the attached file.
![A = \left[\begin{array}{ccc} (3)/(4)& (1)/(4)& (1)/(2)\\ 0 & (1)/(2)& 0\\ -(1)/(4)& -(1)/(4) & 0\end{array}\right]](https://img.qammunity.org/2021/formulas/mathematics/college/vfkgpc5u8viy7srxc8wh7fnxi7b6lfndsi.png)
now for given values:
![\left[\begin{array}{ccc} (3)/(4) - \lambda & (1)/(4)& (1)/(2)\\ 0 & (1)/(2) - \lambda & 0\\ -(1)/(4)& -(1)/(4) & 0 -\lambda \end{array}\right]=0 \\\\](https://img.qammunity.org/2021/formulas/mathematics/college/6rc6vjqn56ee63059ex569mxizia29dh2h.png)
![\to ((3)/(4) - \lambda ) [-\lambda ((1)/(2) - \lambda ) -0] - 0 - (1)/(4)[0- (1)/(2) ((1)/(2) - \lambda )] =0 \\\\\to ((3)/(4) - \lambda ) [((\lambda)/(2) + \lambda^2 )] - (1)/(4)[(\lambda)/(2) - (1)/(4)] =0 \\\\\to ((3)/(8)\lambda + (3)/(4) \lambda^2 - (\lambda^2)/(2) - \lambda^3 - (\lambda)/(8) + (1)/(16)=0 \\\\\to (\lambda - (1)/(2)) (\lambda -(1)/(4)) (\lambda - (1)/(2)) =0\\\\](https://img.qammunity.org/2021/formulas/mathematics/college/e6j60mrcqqyri8u02t08svdlk13gk1xbua.png)


In point b:
Its
spectral radius is less than 1 hence matrix is convergent.
In point c:
![\to c^((k+1)) = A x^(k)+C \\\\\to x(0) = \left(\begin{array}{c}3&1&2\end{array}\right) , c = \left(\begin{array}{c}2&2&4\end{array}\right)\\\\ \to x^((k+1)) = \left[\begin{array}{ccc} (3)/(4)& (1)/(4)& (1)/(2)\\ 0 & (1)/(2)& 0\\ -(1)/(4)& -(1)/(4) & 0\end{array}\right] x^k + \left[\begin{array}{c}2&2&4\end{array}\right] \\\\](https://img.qammunity.org/2021/formulas/mathematics/college/83fscmihiuxzuue51gzj2w0iumtnszjl06.png)
after solving the value the answer is
:
![\lim_(k \to \infty) x^k=o = \left[\begin{array}{c}0&0&0\end{array}\right]](https://img.qammunity.org/2021/formulas/mathematics/college/2s2mx7t46d00pidas1aqwodac5pifoveij.png)