Question

49.9 ml of a 0.00292 m stock solution of a certain dye is ddiluted to 1.00 L. the diluted solution has an absorbance of 0.600. what is the molar

Answer 1

Complete Question

49.9 ml of a 0.00292 m stock solution of a certain dye is diluted to 1.00 L. the diluted solution has an absorbance of 0.600. what is the molar absorptivity coefficient of the dye

Answer:

The value is
`\epsilon = 4118.1 \ M^(-1) cm^(-1)`

Step-by-step explanation:

From the question we are told that

The volume of the stock solution is
`V_1 = 49.9 mL = 0.0499 \ L`

The concentration of the stock solution is
`C_1 = 0.00292 \ M`

The volume of the diluted solution is
`V_2 = 1.00 \ L`

The absorbance is
`A = 0.600`

Generally the from the titration equation we have that

`C_1 * V_1 = C_2 * V_2`

=>
`0.00292 * 0.0499 = C_2 * 1`

=>
`C_2 = 0.0001457 \ M`

Generally from Beer's law we have that

`A = \epsilon * l * C_2`

=>
`\epsilon = (A)/( l * C_2 )`

Here l is the length who value is 1 cm because the unit of molar absorptivity coefficient of the dye is
`M^(-1) * cm^(-1)`

So

`\epsilon = (0.600)/( 1 * 0.0001457 )`

=>
`\epsilon = 4118.1 \ M^(-1) cm^(-1)`