Question

I need help with this promblem it’s ALGEBRA 2!

Answer 1

`(f\circ h)(2)=2`

Explanation:

Composite Function

Given f(x) and h(x) real functions, the composite function named
`(f\circ h)(x)` is defined as:

`(f\circ h)(x)=f(h(x))`

It can be found by substituting h into f.

We are given the functions:

`f(x)=2x^2-9x+2`

`h(x)=x^2-4`

It's required to find
`(f\circ h)(2)`

As defined above:

`(f\circ h)(x)=f(h(x))`

Thus:

`(f\circ h)(2)=f(h(2))`

Find h(2):

`h(2)=2^2-4=0`

h(2)=0

Now:

`(f\circ h)(2)=2(0)^2-9(0)+2`

`(f\circ h)(2)=2`