Given:
2 ft³ of clay was mixed into 7 ft³ of soil containing 55% clay.
To find:
Clay content of the mixture.
Solution:
We have,
55% of soil is clay. So,
Clay in soil= 55% of soil
![\text{Clay in soil}=(55)/(100)* 7](https://img.qammunity.org/2021/formulas/mathematics/high-school/gnisca0xj03sabpfhod60otgpq16f5ug17.png)
![\text{Clay in soil}=(385)/(100)](https://img.qammunity.org/2021/formulas/mathematics/high-school/gu19dob3a7mu231ul3x7r5evxnje3wir5g.png)
![\text{Clay in soil}=3.85](https://img.qammunity.org/2021/formulas/mathematics/high-school/5xzzdx1o04xoc1yrzjb3xoyk551bt3w3u0.png)
2 ft³ of clay was mixed into the soil. So, the total clay content of the mixture is
![2+3.85=5.85\text{ ft}^3](https://img.qammunity.org/2021/formulas/mathematics/high-school/lsfphsb3dne5tjwsb2t13yj6sleppelux4.png)
Therefore, the clay continent in the mixture is 5.85 ft³.