Given:
One sixth of a number, p, is 5 more than two thirds another number, q.
To find:
The value of q.
Solution:
Consider p be a number.
One sixth of a number p:
![(1)/(6)p](https://img.qammunity.org/2021/formulas/mathematics/high-school/4nceebg5weo0t3nstpy5mgy5kcv7ywd4yj.png)
Another number be q.
Two thirds another number q:
![(2)/(3)q](https://img.qammunity.org/2021/formulas/mathematics/high-school/mo6cm393uh50ltrv17i4bferd84zk48mqs.png)
5 more than two thirds another number q:
![(2)/(3)q+5](https://img.qammunity.org/2021/formulas/mathematics/high-school/7rwm6pfl5adttj28p6pk7uogvh9tk1wmcf.png)
According to the question, one sixth of a number p is equal to 5 more than two thirds another number q.
![(1)/(6)p=(2)/(3)q+5](https://img.qammunity.org/2021/formulas/mathematics/high-school/1hloy9bj1y1qtzategypn8stneyay9fa7b.png)
Subtract 5 from both sides.
![(1)/(6)p-5=(2)/(3)q](https://img.qammunity.org/2021/formulas/mathematics/high-school/i9qgmd5utx00ow5aikwzte67we2588zf80.png)
Multiply both sides by
.
![(3)/(2)((1)/(6)p-5)=(3)/(2)* (2)/(3)q](https://img.qammunity.org/2021/formulas/mathematics/high-school/v5sch39ltrswt824oqor0tyt7ejyzvnv3f.png)
![(3)/(2)((1)/(6)p)+(3)/(2)(-5)=q](https://img.qammunity.org/2021/formulas/mathematics/high-school/sp5frnar3ubvqaaiks5edu8i6gkrph7yp4.png)
![(1)/(4)p-(15)/(2)=q](https://img.qammunity.org/2021/formulas/mathematics/high-school/wgnbxciq6571z1njt0wfglfyxagte42tmz.png)
Therefore, the required solution is
.