Question

A truck travels at 74m/s, it travels 250 m then comes to a stop. How fast was the truck accelerating?

Answer 1

acceleration = - 10.952

Step-by-step explanation:

Since it was traveling at 74m/s initially, initial velocity - 74m/s.

Second, since it came to a stop, final velocity - 0 m/s.

Displacement - 250 m.

Use the kinematic equation to solve for acceleration.

`v_f^2 = v_i^2 + 2ax`

0^2 = 74^2 + 2(a)(250)

0 = 5476 + 500a

-5476 = 500a

a = -5476 / 500 = -10.952