Question

For the reaction: 4Fe+3O2= 2Fe2O3 if 100g of Fe are used how much of O2 is used

Answer 1

Mass = 42.88 g

Step-by-step explanation:

Given data:

Mass of iron = 100 g

Mass of O₂ = ?

Solution:

Chemical equation:

4Fe + 3O₂ → 2Fe₂O₃

Number of moles of Iron:

Number of moles = mass/molar mass

Number of moles = 100 g/ 55.85 g/mol

Number of moles = 1.79 mol

Now we will compare the moles iron with oxygen.

Fe : O₂

4 : 3

1.79 : 3/4×1.79 = 1.34 mol

Mass of oxygen used:

Mass = number of moles × molar mass

Mass = 1.34 mol × 32 g/mol

Mass = 42.88 g