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Determine the center and radius of the following circle equation:

x2 + y2 – 12x + 12y + 23 = 0
Help ASAP pls!!!
*It’s hw*

Determine the center and radius of the following circle equation: x2 + y2 – 12x + 12y-example-1
User Turboladen
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1 Answer

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Answer:

  • The center = (a, b) = (6, -6)
  • r = 7

Explanation:

Given the equation


x^2\:+\:y^2\:-\:12x\:+\:12y\:+\:23\:=\:0

We know that a circle equation with a radius 'r', centered at (a, b)


\left(x-a\right)^2+\left(y-b\right)^2=r^2

Rewriting
x^2\:+\:y^2\:-\:12x\:+\:12y\:+\:23\:=\:0 in the form of the standard circle equation


\left(x-6\right)^2+\left(y-\left(-6\right)\right)^2=7^2

Thus,

  • The center = (a, b) = (6, -6)
  • r = 7
User Flying Thunder
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