Question

4(8(a+g)+2z) this is on my maths test and I normally skip through the work so I have no idea what I'm doing

Answer 1

Solving the expression:
`4(8(a+g)+2z)` we get
`\mathbf{32a+32g+8z}`

Explanation:

We need to solve the expression:
`4(8(a+g)+2z)`

First we will multiply 8 with terms inside the bracket

`4(8(a+g)+2z) \\=4(8a+8g+2z)`

The terms inside the bracket are not like terms so, we will simply multiply 4 with terms inside the bracket.

`=4(8a+8g+2z)\\=32a+32g+8z`

So, solving the expression:
`4(8(a+g)+2z)` we get
`\mathbf{32a+32g+8z}`